Example: Extract all files to a different directory # importing shutil moduleįilename = "/home/User/Desktop/filename.zip" If not provided the current working directory is used as the target directory. pathlib.Path instances) that represents the path of the target directory where the file is unpacked. It represents the full path of the file.Įxtract_dir (optional) - It can be any path-like object (e.g. tar.gz, etc)įilename - It can be any path-like object (e.g. Unpack_archive - It detects the compression format automatically from the "extension" of the filename (.zip. Syntax shutil.unpack_archive(filename , extract_dir) Parameters It uses unpack.archive() to unpack the file, Let us look at the below example to understand it. It performs high-level operations on files and the collection of files. It is a higher-level function as compared to zipfile. Instead of using zipfile the alternate is shutil module. Zipfile provides specific properties to unzip files but it is a somewhat low-level library module. List of extracted files- roll7.txt roll8.txt roll10.txt With zipfile.ZipFile("user.zip","r") as f:į.extractall('students',members = list_of_files) We make a list containing the names of the necessary files and pass this list as a parameter to extractall() function. , roll50) and we need to extract just the data of those students whose roll no is 7, 8, and 10. In the given example, we used a dataset of 50 students (namely- roll1, roll2. We can unzip just those files which we need by passing a list of names of the files. This method will unzip and extract only a particular list of files from all the files in the archive. from zipfile import ZipFileį.extractall('dir') Example: Extract selected files to a different directory We pass the destination location as an argument in extractall(). In the given example, the directory does not exist so we name our new directory as "dir" to place all extracted files from "filename.zip". #import zipfile moduleĮxample: Extract all files to a different directory If the file path argument is provided, then it will overwrite the path. It will extract all the files in the current directory. To unzip it first create a ZipFile object by opening the zip file in read mode and then call extractall() on that object. In the given example, we have a zip file in our current directory. Pwd - If the zip file is encrypted then the password is given, the default is None.Įxample: Extract all files to the current directory Members - It shows the list of files to be unzipped, if not provided it will unzip all the files. Path - It is the location where the zip file is unzipped, if not provided it will unzip the contents in the current directory. Syntax extractall(path, members, pwd) Parameters Let us look at the syntax first and then the following examples. We can use zipfile.extractall() function to unzip the file contents in the same directory as well as in a different directory. Its extractall() function is used to extract all the files and folders present in the zip file. Python ZipFile module provides several methods to handle file compress operations. Let's learn about different ways to unzip a file in Python and saving the files in the same or different directory. We need zip files to lessen storage necessities and to improve transfer speed over standard connections.Ī zip folder consisted of several files, in order to use the contents of a zip folder, we need to unzip the folder and extract the documents inside it. Python ZipFile is a class of zipfile module for reading and writing zip files. A zip file is a single file containing one or more compressed files, offering an easy way to make large files smaller and keep related files together. ZIP is the archive file format that permits the first information to be totally recreated from the compacted information. Let's first have a quick look over what is a zip file and why we use it. We will use some built-in functions, some simple approaches, and some custom codes as well to better understand the topic. Let me know if this is possible.In this article, we will learn how one can perform unzipping of a file in Python. I am trying to avoid having to create another process to FTP the file to disk and then read from it. It doesn't have a Filename and isn't located on disk, I only have the byte data in memory. The code example accepts a String Filename. It looks like the code in sciuriware's first reply (pasted below) would work assuming I can find a way to create a File object.
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